Hybridization (Chemistry – Chemical Bonding) MCQs

Hybridization is due to the overlapping of
(a) Orbitals of different energy levels
(b) Orbitals of different energy content
(c) Orbitals of the same energy content
(d) None of the above

Ans. (c)

The valency of carbon is four. On what principle it can be explained in a better way
(a) Resonance
(b) Hybridization
(c) Electron transfer
(d) None of the above

Ans. (b)

The bond angle is minimal in
(a) H₂Te
(b) H₂Se
(c) H₂O
(d) H₂S

Ans. (a)

In sp hybridisation, shape is
(a) Angular
(b) Tetrahedral
(c) Bipyramidal
(d) Linear

Ans. (d)

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The two types of bonds present in B₂H₆ are covalent and
(a) Three center bonds
(b) Hydrogen bond
(c) Two center bonds

Ans. (a)

The ammonium ion is
(a) Tetrahedral
(b) Trigonal pyramidal
(c) Square planar
(d) Square pyramidal

Ans. (a)

The number of unpaired electrons in O₂ molecule is
(a) 0
(b) 1
(c) 2
(d) 3

Ans. (c)

In graphite, electrons are
(a) Localised on every third atom
(b) Present in antibonding orbital
(c) Localised on each C atom
(d) Spread out between the structure

Ans. (d)

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In which compound, the hydrogen bonding is the strongest in its liquid phase?
(a) HF
(b) HI
(c) CH₄
(d) PH₃

Ans. (a)

As the p– character increases, the bond angle in hybrid orbitals formed by s and atomic orbitals
(a) Decreases
(b) Increases
(c) Doubles
(d) Remains unchanged

Ans. (a)

The structure of H₂O₂ is
(a) Planar
(b) Non-planar
(c) Spherical
(d) Linear

Ans. (b)

Which one is false in the following statements?
(a) Each carbon in ethylene is in sp² hybridisation
(b) Each carbon in acetylene is in sp³ hybridisation
(c) Each carbon in benzene is in sp² hybridisation
(d) Each carbon in ethane is in sp³ hybridisation

Ans. (b)

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The two carbon atoms in acetylene are
(a) sp³ hybridized
(b) sp² hybridized
(c) sp hybridized
(d) Unhybridized

Ans. (c)

In benzene molecule all C – C bond lengths are equal because
(a) All carbon atoms are equivalent
(b) All carbon atoms are sp² hybridised
(c) All C – C bonds in benzene, have same order
(d) All C – C bonds are single covalent bond

Ans. (c)

Which one has sp²–hybridization?
(a) CO₂
(b) N₂O
(c) SO₂
(d) CO

Ans. (c)

The structure and hybridisation of Si(CH₃)₄ is
(a) Bent, sp
(b) Trigonal, sp²(c) Octahedral, sp³d
(d) Tetrahedral, sp³

Ans. (d)

Which species does not have sp³ hybridization?
(a) Ammonia
(b) Methane
(c) Water
(d) Carbon dioxide

Ans. (d)

The structure of PF₅ molecule is
(a) Tetrahedral
(b) Trigonal bipyramidal
(c) Square planar
(d) Pentagonal bipyramidal

Ans. (b)

The type of hybridisation of boron in diborane is
(a) sp – hybridization
(b) sp²– hybridization
(c) sp³ –hybridization
(d) sp³d² – hybridization

Ans. (c)

In diborane, the H – B – H bond angle is 120^o. The hybridization of boron is likely to be
(a) sp
(b) sp²(c) sp³
(d) dsp²

Ans. (c)

The shape of XeF₄ molecule is
(a) Linear
(b) Pyramidal
(c) Tetrahedral
(d) Square planar

Ans. (d)

The shape of IF₇ molecule is
(a) Octahedral
(b) Pentagonal bipyramidal(c) Trigonal bipyramidal
(d) Tetrahedral

Ans. (b)

The shapes of BCl₃, PCl₃and ICl₃molecules are all
(a) Triangular
(b) Pyramidal
(c) T– shaped

Ans. (a)

The molecule of CO₂ has a 180° bond angle. It can be explained on the basis of
(a) sp³ hybridization
(b) sp² hybridization
(c) sp hybridization
(d) d²sp³ hybridization

Ans. (d)

Compounds formed by sp³d hybridization will have structure
(a) Planar
(b) Pyramidal
(c) Angular
(d) Trigonal bipyramidal

Ans. (d)

As the s-character of hybridisation orbital increases, the bond angle
(a) Increases
(b) Decreases
(c) Becomes zero
(d) Does not change

Ans. (a)

Among the following compounds, which one is planar in shape?
(a) Methane
(b) Acetylene
(c) Benzene
(d) Isobutene

Ans. (c)

Acetate ion contains
(a) One C, O single bond and one C, O double bond
(b) Two C, O single bonds
(c) Two C, O ouble bonds

Ans. (a)

Hybridization involves
(a) Addition of an electron pair
(b) Mixing up of atomic orbitals
(c) Removal of an electron pair
(d) Separation of orbitals

Ans. (b)

In the complex [SbF₅]^2–, sp³d hybridization is present. The geometry of the complex is
(a) Square
(b) Square pyramidal
(c) Square bipyramidal
(d) Tetrahedral

Ans. (b)

XeF₂ involves hybridization
(a) sp³
(b) sp³d
(c) sp³d²

Ans. (b)

A completely filled d orbital (d¹⁰)
(a) Spherically symmetrical
(b) Has octahedral symmetry
(c) Has tetrahedral symmetry
(d) Depends on the atom

Ans. (b)

Compound having planar symmetry is
(a) H₂SO₄
(b) H₂O
(c) HNO₃
(d) CCL₄

Ans. (c)

Shape of methane molecule is
(a) Tetrahedral
(b) Pyramidal
(c) Octahedral
(d) Square planer

Ans. (a)

The number of shared electrons between carbon-carbon atoms in an ethylene molecule is
(a) 2
(b) 4
(c) 6
(d) 3

Ans. (b)

When the hybridisation state of carbon atom changes from sp³ to sp² to sp, the angle between the hybridised orbitals
(a) Decreases gradually
(b) Increases gradually
(c) Decreases considerably
(d) All of these

Ans. (b)

Which of the following molecules has trigonal planer geometry?
(a) IF₃
(b) PCl₃(c) NH₃
(d) BF₃

Ans. (d)

Structure of ammonia is
(a) Trigonal
(b) Tetrahedral
(c) Pyramidal
(d) Trigonal pyramidal

Ans. (c)

The geometry and the type of hybrid orbital present in the central atom in BF₃ is
(a) Linear, sp
(b) Trigonal planar, sp²(c) Tetrahedral, sp³
(d) Pyramidal, sp³

Ans. (b)

In a regular octahedral molecule, MX₆, the number X – M – X bonds at 180° is
(a) Six
(b) Four(c) Three
(d) Two

Ans. (c)

Be in BeCl₂ undergoes
(a) Diagonal hybridization
(b) Trigonal hybridization
(c) Tetrahedral hybridization
(d) No hybridization

Ans. (a)

Shape of BF₃ molecule is
(a) Linear
(b) Planar
(c) Tetrahedral
(d) Square pyramidal

Ans. (b)

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The bond angle in water molecules is nearly or Directed bonds in water forms an angle of
(a) 120^o
(b) 180^o(c) 109^o 28’
(d) 104^o 30’

Ans. (d)

When two pairs of electrons are shared, bond is?
(a) Single covalent bond
(b) Double covalent bond
(c) Dative bond
(d) Triple bond

Ans. (b)

The central atom in a molecule is in hybrid state. The shape of molecule will be
(a) Pyramidal
(b) Tetrahedral
(c) Octahedral
(d) Trigonal planar

Ans. (d)

sp³d² hybrid orbitals are
(a) Linear bipyramidal
(b) Pentagonal(c) Trigonal bipyramidal
(d) Octahedral

Ans. (d)

Carbon atoms in diamond are bonded to each other in a configuration
(a) Tetrahedral
(b) Planar
(c) Linear
(d) Octahedral

Ans. (a)

In benzene, all the six C – C bonds have the same length because of
(a) Tautomerism
(b) sp² hybridization
(c) Isomerism
(d) Inductive effect

Ans. (b)

The nature of hybridization in the NH₃ molecule is
(a) sp
(b) sp²(c) sp³
(d) sp³d

Ans. (c)

The geometry of the molecule with sp³d² hybridised central atom is
(a) Square planar
(b) Trigonal bipyramidal
(c) Octahedral
(d) Square pyramidal

Ans. (c)

Geometry of ammonia molecule and the hybridization of nitrogen involved in it are
(a) sp³ –hybridization and tetrahedral geometry
(b) sp³ –hybridization and distorted tetrahedral geometry
(c) sp² –hybridization and triangular geometry

Ans. (b)