Objective type questions on Electric Current, Ohm’s Law, Resistance, Kirchhoff’s Law, Measuring Instruments and current electricity with answers.

## Electric Current Physics

Question 1 |

It is easier to start a car engine on a hot day than on a cold day. This is because the internal resistance of the car battery

Increases with rise in temperature | |

Decreases with rise in temperature | |

Does not change with a change in temperature | |

Decreases with a fall in temperature |

Question 2 |

A uniform wire of resistance 9 ohm is cut into 3 equal parts. They are connected in the form of equilateral triangle

*ABC*. A cell of e.m.f. 2*V*and negligible internal resistance is connected across*B*and*C*. Potential difference across*AB*is3 V | |

1 V | |

0.5 V | |

2 V |

Question 3 |

By increasing the temperature, the specific resistance of a conductor and a semiconductor

Increases for both | |

Increases, decreases | |

Decreases, increases | |

Decreases for both |

Question 4 |

Current provided by a battery is maximum when

None of these | |

Internal resistance equal to external resistance | |

Internal resistance is greater than external resistance | |

Internal resistance is less than external resistance |

Question 5 |

For driving a current of 2

*A*for 6*minutes*in a circuit, 1000*J*of work is to be done. The e.m.f. of the source in the circuit is1.38 V | |

3.10 V | |

2.04 V | |

1.68 V |

Question 6 |

An ammeter whose resistance is 180 ohm gives full scale deflection when current is 2

*mA*. The shunt required to convert it into an ammeter reading 20*mA*(in*ohm*s) is10 | |

20 | |

18 | |

0.1 |

Question 7 |

An energy source will supply a constant current into the load if its internal resistance is

Very large as compared to the load resistance | |

Equal to the resistance of the load | |

Zero | |

Non-zero but less than the resistance of the load |

Question 8 |

Potential gradient is defined as

Potential at any one end of the wire | |

Fall of potential between two ends of the wire | |

Fall of potential per unit area of the wire | |

Fall of potential per unit length of the wire |

Question 9 |

A potentiometer having the potential gradient of 2

*mV*/*cm*is used to measure the difference of potential across a resistance of 10*ohm*. If a length of 50*cm*of the potentiometer wire is required to get the null point, the current passing through the 10*ohm*resistor is (in*mA*)2 | |

1 | |

5 | |

10 |

Question 10 |

If a 0.1 % increase in length due to stretching, the percentage increase in its resistance will be

0.1 % | |

0.2 % | |

1 % | |

2 % |

Question 11 |

The length of the wire is doubled. Its conductance will be

Unchanged | |

Quadrupled | |

Halved | |

1/4 of the original value |

Question 12 |

The internal resistance of a cell depends on

The area of the plates immersed | |

The concentration of the electrolyte | |

All the these | |

The distance between the plates |

Question 13 |

The resistivity of a wire depends on its

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Area of cross-section | |

Material | |

Length | |

Shape |

Question 14 |

The tangent galvanometer, when connected in series with a standard resistance can be used as

An ammeter | |

A voltmeter | |

Both an ammeter and a voltmeter | |

A wattmeter |

Question 15 |

A torch battery consisting of two cells of 1.45

*volts*and an internal resistance 0.15 ohm, each cell sending currents through the filament of the lamps having resistance 1.5*ohm*s. The value of current will be16.11 amp | |

1.611 amp | |

0.1611 amp | |

2.6 amp |

Question 16 |

The reciprocal of resistance is

Voltage | |

Resistivity | |

None of these | |

Conductance |

Question 17 |

Which is a

*wrong*statementThe rheostat can be used as a potential divider | |

Kirchhoff's first law (for currents meeting at a junction in an electric circuit) expresses the conservation of charge | |

The Wheatstone bridge is most sensitive when all the four resistances are of the same order | |

In a balanced Wheatstone bridge, interchanging the positions of galvanometer and cell affects the balance of the bridge |

Question 18 |

A galvanometer can be converted into an ammeter by connecting

Low resistance in parallel | |

High resistance in series | |

High resistance in parallel | |

Low resistance in series |

Question 19 |

The material of wire of potentiometer is

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Copper | |

Manganin | |

Aluminium | |

Steel |

Question 20 |

The resistance of a conductor is 5

*ohm*at 50^{o}*C*and 6*ohm*at 100^{o}*C*. Its resistance at 0^{o}*C*is1 ohm | |

4 ohm | |

3 ohm | |

2 ohm |

Question 21 |

A copper wire of resistance

*R*is cut into ten parts of equal length. Two pieces each are joined in series and then five such combinations are joined in parallel. The new combination will have a resistanceR/5 | |

R/25 | |

R | |

R/4 |

Question 22 |

Resistance in the two gaps of a

*meter*bridge are 10*ohm*and 30*ohm*respectively. If the resistances are interchanged the balance point shifts by66.67cm | |

50 cm | |

33.3 cm | |

25 cm |

Question 23 |

A potentiometer consists of a wire of length 4

*m*and resistance 10 ohm. It is connected to a cell of e.m.f. 2*V*. The potential difference per unit length of the wire will be0.5 V/m | |

10 V/m | |

2 V/m | |

5 V/m |

Question 24 |

A wire of resistance R is divided in 10 equal parts. These parts are connected in parallel, the equivalent resistance of such connection will be

0.01 R | |

10 R | |

0.1 R | |

100 R |

Question 25 |

The equivalent resistance of resistors connected in series is always

Equal to sum of component resistors | |

Equal to the mean of component resistors | |

In between the lowest and the highest of component resistors | |

Less than the lowest of component resistors |

Question 26 |

A piece of wire of resistance 4

*ohm*s is bent through 180^{o}at its mid point and the two halves are twisted together, then the resistance is1 ohm | |

8 ohms | |

5 ohms | |

2 ohms |

Question 27 |

By a cell a current of 0.9 A flows through 2

*ohm*resistor and 0.3 A through 7*ohm*resistor. The internal resistance of the cell is1.2 ohm | |

0.5 ohm | |

2.0 ohm | |

1.0 ohm |

Question 28 |

If resistance of voltmeter is 10000 ohm and resistance of ammeter is 2 ohm then find

*R*when voltmeter reads 12*V*and ammeter reads 0.1*A*124 ohm | |

120 ohm | |

114 ohm | |

118 ohm |

Question 29 |

The current in a simple series circuit is 5.0

*amp*. When an additional resistance of 2.0*ohms*is inserted, the current drops to 4.0*amp*. The original resistance of the circuit in ohms was20 | |

10 | |

8 | |

1.25 |

There are 29 questions to complete.

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